Proving by contradiction: (a/b)^2 = 2 Multiplying both sides by b^2, we get: a^2 = 2b^2 The right side is even, therefore a^2 is even. However, in order for the square of a number to be even, the number itself must be even. Lets claim: a = 2f Substitute for a: (2f)^2 = 2b^2 4f^2 = 2b^2 2f^2 = b^2 The left side is even, therefore b and b^2 must be even. Now we have found that both a and b are even. Therefore, the assumption is incorrect, and there cannot exist a rational number whose square = 2
Wrong. You put those colors of paint in a single container and you'll have a bucket of light orange paint. It will all be one color. Do you guys know you're probably helping Kickback with some sort of assignment?
Man what's the deal with all the NERDS in here? I thought this place was cool. Shit dawgs, I gotta go pump some iron - I'm throwing up about three hundy.
over...dun dun duhhhhhhhh dundundun....someone's.....yeeeeeeeeaaaaaaaaaahhhhhhhhhhhhhhhhhh.....head.........woooooooooooohhhhhhhoooooooo!!!!!!!!!!!!!!!1
You guys lost me after the fourth question, but i'm proud i got the first one right. Kinda like the Cowboys, win early in the season, then suck and get the shit kicked out of them at the end of the season. He's a shoesaleman married to peg.
DAMN YOU KICKBACK!!!!!!!! My fucking head hurts and you're bringing me back to places I thought I would never have to go to again. ***crawls under desk, MAKE THE BAD MAN STOP***
